JEE Advance - Physics (2010 - Paper 2 Offline - No. 1)
A vernier calipers has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier calipers, the least count is
0.02 mm
0.05 mm
0.1 mm
0.2 mm
Wyjaśnienie
In Vernier scale, 16 mm is divided into 20 parts, that is,
1 VSD = 16/20 mm.
Least count = 1 MSD $$-$$ 1 VSD
$$LC = \left( {1 - {{16} \over {20}}} \right)$$ mm = 0.22 mm